| Title |
Test
Find
Class A Network Number
|
| Expression |
^(10\.[0-9]|[1-9][0-9]|[1-2][0-5][0-5]\.[0-9]|[1-9][0-9]|[1-2][0-5][0-5]\.[0-9]|[1-9][0-9]|[1-2][0-5][0-5])$ |
| Description |
The IANA resrved 24-bit block of IP address space for private internets. It's just a single class A network number. This is also RFC 1918 compliant. |
| Matches |
10.0.0.0 | 10.255.255.255 |
| Non-Matches |
17.16.0.0 | 192.168.255.255 |
| Author |
Rating:
Ted Cambron
|
| Source |
|
| Your Rating |
|
Title: Malfunction
Name: WolfgangBadura@aon.at
Date: 4/17/2008 9:49:28 AM
Comment:
Installed are Win XP SP2 VB 6.0 SP 5 and Microsofts VBScript Regular Expression 5.5.
Each internal address (eg. 192.168.111.19) does not match.
I testet the following pattern and it goes:
\b192\.168\.([0-9]|[1-9][0-9]|[1-9][0-9][0-9])\.([0-9]|[1-9][0-9]|[1-9][0-9][0-9])\b
