Title |
Test
Find
MM/YYYY MONTH/YEAR
|
Expression |
^((0[1-9])|(1[0-2]))\/(\d{4})$ |
Description |
This regular expressions matches dates in the format MM/YYYY where MM can be 01 to 12 and YYYY is always 4 digits long. |
Matches |
12/2002 | 11/1900 | 02/1977 |
Non-Matches |
1/1977 | 00/000 | 15/2002 |
Author |
Rating:
Jony Ferreira
|
Source |
|
Your Rating |
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Title: thanks
Name: MVV
Date: 9/10/2021 8:03:19 PM
Comment:
Thanks
Title: Single- or double-digit month with 19xx or 20xx year
Name: Baller
Date: 9/19/2017 6:01:03 AM
Comment:
m/yyyy or mm/yyyy where yyyy has to start with '19' or '20'
Here you go, fam:
^((0?[1-9])|(1[0-2]))\/(19|20)\d{2}$
Title: 29-Apr-16
Name: Rosanne
Date: 6/23/2016 3:52:45 PM
Comment:
What is the dictionary to change above format to 4/26/2016 please help!!
Title: 29-Apr-16
Name: Rosanne
Date: 6/23/2016 3:52:38 PM
Comment:
What is the dictionary to change above format to 4/26/2016 please help!!
Title: 29-Apr-16
Name: Rosanne
Date: 6/23/2016 3:38:16 PM
Comment:
What is the dictionary to change above format to 4/26/2016 please help!!
Title: M/yyyy AND MM/yyyy format
Name: Sandeep
Date: 8/5/2009 7:40:45 AM
Comment:
^([1-9]|1[0-2]|0[1-9])\/(\d{4})$
Title: M/yyyy AND MM/yyyy format
Name: Sandeep
Date: 8/5/2009 7:40:23 AM
Comment:
^([1-9]|1[0-2]|0[1-9])\/(\d{4})$
Title: M/yyyy format
Name: Sandeep
Date: 8/5/2009 7:31:14 AM
Comment:
What if you wanted to allow a month in the form of a single digit (m/yyyy) as well as the mm/yyyy format (01/2003 and 1/2003)?
Title: Single Month
Name: Andy Spencer
Date: 12/10/2003 12:09:26 PM
Comment:
What if you wanted to allow a month in the form of a single digit (m/yyyy) as well as the mm/yyyy format (01/2003 and 1/2003)?