| Title |
Test
Find
mm/dd/yyyy Julian and Gregrian Datetime
|
| Expression |
(?#Calandar from January 1st 45 BC to December 31, 9999
in mm/dd/yyyy format)
(?!
(?:10(?<sep>[-./])(?:0?[5-9]|1[0-4])\k<sep>(?:1582))| #Missing days from 1582
(?:0?9(?<sep>[-./])(?:0?[3-9]|1[0-3])\k<sep>(?:1752)) #or Missing days from 1752
(?# both sets of missing days such not be in the same calendar
so remove one or the other)
)
(?n:^(?=\d) # the character at the beginning a the sring must be a digit
(
(?<month>
(0?[13578])|1[02]| #months with 31 days
(0?[469]|11)(?!.31)| # months with 30 days
0?2 # February
(?(.29) # if feb 29th check for valid leap year
(?=.29.
(?! #exclude these years from leap year pattern
000[04] #No year 0 and no leap year in year 4
|
(?:(?:1[^0-6]|[2468][^048]|[3579][^26])00)
(?# centurial years > 1500 not evenly divisible by 400
are not leap year)
)
(?:(?:(?:\d\d) # century
(?:[02468][048]|[13579][26]) #leap years
(?!\x20BC))|(?:00(?:42|3[0369]|2[147]|1[258]|09)\x20BC))
)| # else if not Feb 29
(?!.3[01]) # and day not Feb 30 or 31
) #end Leap year check
) #end of month check
(?<sep>[-./]) # choose a date separator
(?<day>0?[1-9]|[12]\d|3[01]) #days between 1-31
(?# The maximum number of days allowed for a month has
already been checked for in the month check.
If you made it this far the number of day is
within the range for the given month)
\k<sep> # Match the same date separator choosen before.
(?!0000) # There is no year 0
(?<year>(?=(?:00(?:4[0-5]|[0-3]?\d)\x20BC)|(?:\d{4}(?:\z|(?:\x20\d))))\d{4}(?:\x20BC)? # a four digit year. Use leading zeros if needed
)
(?(?=\x20\d)\x20|$))? # if there is a space followed by a digit check for time
(?<time>
( # 12 hour format
(0?[1-9]|1[012]) # hours
(:[0-5]\d){0,2} # optional minutes and seconds
(?i:\x20[AP]M) # required AM or PM
)| # 24 hour format
(
[01]\d|2[0-3]) #hours
(:[0-5]\d){1,2}) #required minutes optional seconds
?$) |
| Description |
Datetime for Julian and Gregorian Calenders
Matchs dates from 0001 A.D. to 9999 A.D.
Days and months are 1 or 2 digits
Years are 4 digit with leading zeros if required.
February is validate in all leap years
Leap year rules for Julian and Gregorian calendars (http://scienceworld.wolfram.com/astronomy/LeapYear.html)
Missing days for 1582 and 1752 are not matched. Though only one set should be applied to a calendar since they are caused by when the calendar was adopted
Missing days (http://scienceworld.wolfram.com/astronomy/GregorianCalendar.html)
Time can be either 12 or 24 hour format
12 hour format hh:MM:ss AM|PM
minutes and seconds are optional
24 hour format hh:mm:ss
seconds are optional, hours less than ten require leading zero
Datetome format is a date, a space then a time. |
| Matches |
12/25/0004 | 12/31/0001 BC 2:15 AM | 2-29-2004 09:00 |
| Non-Matches |
00/00/0000 | 2-29-2100 | 10/8/1582 |
| Author |
Rating:
Not yet rated.
Michael Ash
|
| Source |
|
| Your Rating |
|
Title: Javascript Version
Name: Michael Ash
Date: 7/21/2004 4:46:59 PM
Comment:
A Javascript compatible version of this regex can be found at http://www.regexlib.com/REDetails.aspx?regexp_id=761
Title: Stepping back
Name: Michael Ash
Date: 7/21/2004 4:42:05 PM
Comment:
Modified to include Julian dates back to 45 BC.
Title: without most of the comments
Name: Michael Ash
Date: 6/8/2004 2:59:01 PM
Comment:
This is the above expression all but one of the comments removed for ease of use
(?!(?:10(?<sep>[-./])(?:0?[5-9]|1[0-4])\k<sep>(?:1582))|(?:0?9(?<sep>[-./])(?:0?[3-9]|1[0-3])\k<sep>(?:1752))(?# both sets of missing days such not be in the same calendar so remove one or the other))(?n:^(?=\d)((?<month>(0?[13578])|1[02]|(0?[469]|11)(?!.31)|0?2(?(.29)(?=.29.(?!000[04]|(?:(?:1[^0-6]|[2468][^048]|[3579][^26])00))(?:(?:\d\d)(?:[02468][048]|[13579][26])))|(?!.3[01])))(?<sep>[-./])(?<day>0?[1-9]|[12]\d|3[01])\k<sep>(?!0000)(?<year>\d{4})(?(?=\x20\d)\x20))?(?<time>((0?[1-9]|1[012])(:[0-5]\d){0,2}(?i:\x20[AP]M))|([01]\d|2[0-3])(:[0-5]\d){1,2})?$)
This should be one long string with no line breaks
