Title: If the escape character will be that "
Name: Serge
Date: 11/13/2006 7:52:12 AM
Comment:
If the escape character will be that?
Exemple "This is a ""String"
Title: If the escape character will be that?
Name: If the escape character will be that?
Date: 11/13/2006 7:51:01 AM
Comment:
If the escape character will be that?
Exemple "This is a ""String"
Title: developer
Name: Vlad
Date: 8/9/2005 11:30:49 PM
Comment:
thanks. btw, it works even better without first [^"], try: "((?:\\.|[^\\""]*)*)". Changing [^"] to [^"]* kills it.
Title: String literals
Name: Shanmugam Devaraj
Date: 6/23/2005 11:13:33 PM
Comment:
If we need to match string literals, a simple expression like below should be sufficient isn't it?
expression = "^".*"$"
i.e.Begin with double quote and end with double quote and match any characters zero or more times.
This would match
"", """, " ", "test\", "\"test\"", ""test"", ""ErrorMessageCode",1249", "This is a \"string\"." etc...
Title: Thanks Gideon
Name: Darren Neimke
Date: 4/2/2005 11:05:55 PM
Comment:
I'll check this out during the week and then modify my pattern accordingly. Thankyou for taking the time to give me the feedback!
Title: Simpler solution
Name: Gideon Engelberth
Date: 4/2/2005 7:55:25 PM
Comment:
Darren, your modification does allow the expression to match the empty string, but it also now matches "test\"
While Benoit's solution also seems to work, here is a simpler expression that meets the specifications.
"(?:\\.|[^\\"])*"
Title: Empty strings solution!
Name: Benoit d'Oncieu
Date: 3/5/2004 6:10:27 AM
Comment:
Darren Solution does not work as it would match the following: """
The correct regex is:
"([^"](?:\\.|[^\\"]*)*)?"
Title: Re: x
Name: Darren Neimke
Date: 12/12/2003 2:39:34 PM
Comment:
ALTERED 13-Dec-2003
-------------------
Previous pattern was :
"([^"](?:\\.|[^\\"]*)*)"
Changed to:
"([^"]*(?:\\.|[^\\"]*)*)"
Making the first character after the opening quote optional allows the pattern to match on empty quotes: "".
Title: x
Name: Achim
Date: 12/12/2003 3:55:50 AM
Comment:
This expression dowa not work for empty strings ""! Any suggestion how to solve this problem?
